Set.prototype.delete()

The delete() method removes the specified element from a Set object.

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Syntax

mySet.delete(value);

Parameters

value

The value to remove from mySet.

Return value

Returns true if value was successfully removed from mySet; otherwise false.

Examples

Using the delete() method

const mySet = new Set();
mySet.add('foo');

mySet.delete('bar'); // Returns false. No "bar" element found to be deleted.
mySet.delete('foo'); // Returns true.  Successfully removed.

mySet.has('foo');    // Returns false. The "foo" element is no longer present.

Let's checkout below how to delete an Object from a Set.

const setObj = new Set();   // Create a New Set.

setObj.add({x: 10, y: 20}); // Add object in the set.

setObj.add({x: 20, y: 30}); // Add object in the set.

// Delete any point with `x > 10`.
setObj.forEach(function(point){
  if (point.x > 10){
    setObj.delete(point)
  }
})

Specifications

Browser compatibility

See also

• Set
• Set.prototype.clear()