# Math.max()

The `Math.max()` function returns the largest of the zero or more numbers given as input parameters.

## Syntax

`Math.max([value1[, value2[, ...]]])`

### Parameters

`value1, value2, ...`
Numbers.

### Return value

The largest of the given numbers. If any of the arguments are `NaN` or cannot be converted to a number, `NaN` is returned.

## Description

Because `Math` is not a constructor, `max()` is a static method of `Math` (You always use it as `Math.max()`, rather than as a method of an instanced `Math` object).

-`Infinity` is the initial comparant because it is smaller than all other numbers, so that's why when no arguments are given, -`Infinity` is returned.

If any of the arguments are `NaN` or cannot be converted to a number, the result is `NaN`.

## Examples

### Using Math.max()

```Math.max(10, 20);   //  20
Math.max(-10, -20); // -10
Math.max(-10, 20);  //  20
```

### Getting the maximum element of an array

`Array.reduce()` can be used to find the maximum element in a numeric array, by comparing each value:

```var arr = [1,2,3];
var max = arr.reduce(function(a, b) {
return Math.max(a, b);
});
```

The following function uses `Function.prototype.apply()` to get the maximum of an array. `getMaxOfArray([1, 2, 3])` is equivalent to `Math.max(1, 2, 3)`, but you can use `getMaxOfArray()` on programmatically constructed arrays. This should only be used for arrays with relatively few elements.

```function getMaxOfArray(numArray) {
return Math.max.apply(null, numArray);
}```

The new spread operator is a shorter way of writing the `apply` solution to get the maximum of an array:

```var arr = [1, 2, 3];
var max = Math.max(...arr);
```

However, both spread (`...`) and `apply` will either fail or return the wrong result if the array has too many elements, because they try to pass the array elements as function parameters. See Using apply and built-in functions for more details. The `reduce` solution does not have this problem.

## Browser compatibility

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